#JavaScript - find words that can be typed on one keyboard row

Solutions to @cassidoo ^⇗'s code exercise in her newsletter ^⇗

Given an array of words, return the words that can be typed using letters of only one row on a keyboard.

##Tradidional for loops

const keyboardLayout = {
  ansi: [
    '`1234567890-=~!@#$%^&*()_+',
    'qwertyuiop[]\\{}|',
    `asdfghjkl;':"`,
    'zxcvbnm,./<>?',
  ],
  dvorak: [
    '`1234567890[]~!@#$%^&*(){}',
    `'",<.>pyfgcrl?/+=|\\`,
    'aoeuidhtns-_',
    ':;qjkxbmwvz',
  ],
  // fill more keyboard layouts here
}

const oneRow = (wordList, layout = 'ansi') => {
  const result = []

  for (let i = 0; i < wordList.length; i += 1) {
    const word = wordList[i]

    for (let j = 0; j < keyboardLayout[layout].length; j += 1) {
      let isOnOneRow = true
      for (let k = 0; k < word.length; k += 1) {
        if (!keyboardLayout[layout][j].includes(word[k])) {
          isOnOneRow = false
          break
        }
      }

      if (isOnOneRow) {
        result.push(word)
        break
      }
    }
  }

  return result
}

oneRow(['candy', 'doodle', 'pop', 'shield', 'lag', 'typewriter'])
// ['pop', 'lag', 'typewriter']

##Using array methods

const keyboardLayout = {
  ansi: [
    '`1234567890-=~!@#$%^&*()_+',
    'qwertyuiop[]\\{}|',
    `asdfghjkl;':"`,
    'zxcvbnm,./<>?',
  ],
  dvorak: [
    '`1234567890[]~!@#$%^&*(){}',
    `'",<.>pyfgcrl?/+=|\\`,
    'aoeuidhtns-_',
    ':;qjkxbmwvz',
  ],
  // fill more keyboard layouts here
}

const isTypeableOnOneRow = (layout) => (word) => {
  const characters = word.toLowerCase().split('')

  return keyboardLayout[layout.toLowerCase()].some((row) =>
    characters.every((character) => row.includes(character)),
  )
}

const oneRow = (wordList, layout = 'ansi') =>
  wordList.filter(isTypeableOnOneRow(layout))

oneRow(['candy', 'doodle', 'pop', 'shield', 'lag', 'typewriter'])
// ['pop', 'lag', 'typewriter']